This is the memory layout before allocating chunks:

	Address		Chunk/hole
	--------------------------
	0               1024-byte chunk
	1024            128-byte  hole   
	1152            1024-byte chunk
	2176            512-byte  hole  
	2688            1024-byte chunk
	3712            32-byte   hole   
	3744            1024-byte chunk
	4768            64-byte   hole
	4832            1024-byte chunk


Question #1:
	The allocator allocates chunks at the BEGINNING of holes.
	If if did allocate at the end, the 32-byte chunk
        would have been allocated at address 4832-32 = 4800. Instead
        it was allocated at address 4768.

Question #2:
	None of the above

Question #3:
	Best Fit
	
Question #4:

	The 90-byte chunk was allocated at address 1024
	The 20-byte chunk was allocated at address 3712
	The 30-byte chunk was allocated at address 1114
	The 20-byte chunk was allocated at address 4768